Optimal. Leaf size=73 \[ \frac{a^2 (B-C) \sin (c+d x)}{d}+\frac{a^2 (B+2 C) \tanh ^{-1}(\sin (c+d x))}{d}+a^2 x (2 B+C)+\frac{C \sin (c+d x) \left (a^2 \sec (c+d x)+a^2\right )}{d} \]
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Rubi [A] time = 0.206269, antiderivative size = 73, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.1, Rules used = {4072, 4018, 3996, 3770} \[ \frac{a^2 (B-C) \sin (c+d x)}{d}+\frac{a^2 (B+2 C) \tanh ^{-1}(\sin (c+d x))}{d}+a^2 x (2 B+C)+\frac{C \sin (c+d x) \left (a^2 \sec (c+d x)+a^2\right )}{d} \]
Antiderivative was successfully verified.
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Rule 4072
Rule 4018
Rule 3996
Rule 3770
Rubi steps
\begin{align*} \int \cos ^2(c+d x) (a+a \sec (c+d x))^2 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\int \cos (c+d x) (a+a \sec (c+d x))^2 (B+C \sec (c+d x)) \, dx\\ &=\frac{C \left (a^2+a^2 \sec (c+d x)\right ) \sin (c+d x)}{d}+\int \cos (c+d x) (a+a \sec (c+d x)) (a (B-C)+a (B+2 C) \sec (c+d x)) \, dx\\ &=\frac{a^2 (B-C) \sin (c+d x)}{d}+\frac{C \left (a^2+a^2 \sec (c+d x)\right ) \sin (c+d x)}{d}-\int \left (-a^2 (2 B+C)-a^2 (B+2 C) \sec (c+d x)\right ) \, dx\\ &=a^2 (2 B+C) x+\frac{a^2 (B-C) \sin (c+d x)}{d}+\frac{C \left (a^2+a^2 \sec (c+d x)\right ) \sin (c+d x)}{d}+\left (a^2 (B+2 C)\right ) \int \sec (c+d x) \, dx\\ &=a^2 (2 B+C) x+\frac{a^2 (B+2 C) \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a^2 (B-C) \sin (c+d x)}{d}+\frac{C \left (a^2+a^2 \sec (c+d x)\right ) \sin (c+d x)}{d}\\ \end{align*}
Mathematica [A] time = 0.317977, size = 143, normalized size = 1.96 \[ \frac{a^2 \left (B \sin (c+d x)-B \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+B \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )+2 B c+2 B d x+C \tan (c+d x)-2 C \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+2 C \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )+c C+C d x\right )}{d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.072, size = 107, normalized size = 1.5 \begin{align*} 2\,{a}^{2}Bx+{a}^{2}Cx+{\frac{B{a}^{2}\sin \left ( dx+c \right ) }{d}}+{\frac{B{a}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+2\,{\frac{B{a}^{2}c}{d}}+{\frac{{a}^{2}C\tan \left ( dx+c \right ) }{d}}+2\,{\frac{{a}^{2}C\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+{\frac{C{a}^{2}c}{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.94135, size = 142, normalized size = 1.95 \begin{align*} \frac{4 \,{\left (d x + c\right )} B a^{2} + 2 \,{\left (d x + c\right )} C a^{2} + B a^{2}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 2 \, C a^{2}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 2 \, B a^{2} \sin \left (d x + c\right ) + 2 \, C a^{2} \tan \left (d x + c\right )}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.516101, size = 278, normalized size = 3.81 \begin{align*} \frac{2 \,{\left (2 \, B + C\right )} a^{2} d x \cos \left (d x + c\right ) +{\left (B + 2 \, C\right )} a^{2} \cos \left (d x + c\right ) \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (B + 2 \, C\right )} a^{2} \cos \left (d x + c\right ) \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (B a^{2} \cos \left (d x + c\right ) + C a^{2}\right )} \sin \left (d x + c\right )}{2 \, d \cos \left (d x + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.16266, size = 212, normalized size = 2.9 \begin{align*} \frac{{\left (2 \, B a^{2} + C a^{2}\right )}{\left (d x + c\right )} +{\left (B a^{2} + 2 \, C a^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) -{\left (B a^{2} + 2 \, C a^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) + \frac{2 \,{\left (B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 1}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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